Question 2 of 10
How many real number solutions are there to the equation 0 = –3x² + x – 4?
A. 0
B. 1
C. 2
D. 3
C is wrong, since the discriminant is negative.
Looks like A to me.
You are correct. The discriminant of the quadratic equation is:
b² - 4ac = 1 - 4(-3)(-4) = 49
Since the discriminant is positive, there are real number solutions. However, there are no solutions that satisfy the equation because the quadratic equation has no real roots. Therefore, the answer is A. 0.
To find the number of real number solutions to the equation 0 = -3x² + x - 4, we can use the discriminant of the quadratic equation. The discriminant is given by the formula D = b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.
In this case, a = -3, b = 1, and c = -4. Let's calculate the discriminant:
D = (1)² - 4(-3)(-4)
= 1 - 48
= -47
Since the discriminant is negative (-47 < 0), there are no real number solutions to the equation. Therefore, the correct answer is:
A. 0