Bob's gift shop sold a record number of cards for Mother's Day. One salesman sold 30 cards, which was 20% of the cards sold for Mother's Day. How many cards were sold for Mother's Day?
Insert the values given in the problem then scale up or down to find the missing value.
Let x be the total number of cards sold for Mother's Day.
We know that one salesman sold 30 cards, which is 20% of the total number of cards sold:
0.20 * x = 30
To solve for x, we can divide both sides by 0.20:
x = 150
Therefore, a total of 150 cards were sold for Mother's Day.
All students in Ridgewood Junior High School either get their lunch in the school cafeteria or brought it from home on Tuesday. 10% of students brought their lunch. 48 students brought their lunch. How many students in total are in Ridgewood Junior High School?
Insert the values given in the problem then scale up or down to find the missing value.
Let x be the total number of students in Ridgewood Junior High School.
We know that 10% of students brought their lunch, which means 90% got their lunch from the cafeteria:
0.10x = 48 (number of students who brought their lunch)
To solve for x, we can divide both sides by 0.10:
x = 480
Therefore, there are a total of 480 students in Ridgewood Junior High School.
Find the mean of the scores to the nearest 10th
55 8
60 5
65 4
70 8
75 2
80 4
85 1
90 7
To find the mean, we need to first find the sum of all the scores, and then divide by the total number of scores:
(55*8) + (60*5) + (65*4) + (70*8) + (75*2) + (80*4) + (85*1) + (90*7) = 4535
Total number of scores = 39
Mean = 4535/39 ≈ 116.0 (rounded to the nearest 10th)
Therefore, the mean of the scores is approximately 116.0.
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score 55 Number of Students 8
Score 60 Number of Students 5
Score 65 Number of Students 4
Score 70 Number of Students 8
Score 75 Number of Students 2
Score 80 Number of Students 4
Score 85 Number of Students 1
Score 90 Number of Students 7
To find the mean, we need to first find the sum of all the scores, and then divide by the total number of students:
(55 x 8) + (60 x 5) + (65 x 4) + (70 x 8) + (75 x 2) + (80 x 4) + (85 x 1) + (90 x 7) = 4535
Total number of students = 39
Mean = 4535/39 ≈ 116.0 (rounded to the nearest 10th)
Therefore, the mean score is approximately 116.0.
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score Number of Students
70
70
8
8
75
75
2
2
80
80
9
9
85
85
1
1
90
90
7
7
95
95
6
6
To find the mean, we need to first find the sum of all the scores, and then divide by the total number of students:
(70 x 2) + (75 x 2) + (80 x 9) + (85 x 1) + (90 x 7) + (95 x 6) = 1920
Total number of students = 27
Mean = 1920/27 ≈ 71.1 (rounded to the nearest 10th)
Therefore, the mean score is approximately 71.1.
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score Number of Students
80
80
7
7
85
85
3
3
90
90
5
5
95
95
4
4
100
100
5
5