How much of heat is needed to warm 500 g of water from 25 °C near to its boiling point of 99°C? The specific heat of capacity is 4.18J/g-k.
The formula to calculate the heat required to warm a substance is:
Q = m × c × ΔT
where:
Q = heat required (in Joules)
m = mass of substance (in grams)
c = specific heat capacity of substance (in J/g-K)
ΔT = change in temperature (in K or °C)
So, using this formula:
Q = 500 g × 4.18 J/g-K × (99°C - 25°C)
Q = 500 g × 4.18 J/g-K × 74°C
Q = 155,320 Joules
Therefore, 155,320 Joules of heat is needed to warm 500 g of water from 25°C near to its boiling point of 99°C.
To calculate the amount of heat needed to warm 500 g of water from 25 °C to near its boiling point of 99 °C, we will use the equation:
Q = m * c * ΔT
Where:
Q = heat (in Joules)
m = mass of the water (in grams)
c = specific heat capacity of water (in J/g-K)
ΔT = change in temperature (in degrees Celsius)
Given:
m = 500 g
c = 4.18 J/g-K
ΔT = 99 °C - 25 °C = 74 °C
Plugging in these values, we have:
Q = 500 g * 4.18 J/g-K * 74 °C
Calculating this:
Q = 155860 J
Therefore, it would take approximately 155,860 Joules of heat to warm 500 g of water from 25 °C to near its boiling point of 99 °C.