Use the image to answer the question.
An illustration shows a two-dimensional net of a triangular prism with all of its sides open and visible. The net appears as three vertical rectangles joined next to each other. All 4 sides of the middle rectangle are drawn with dashed lines. The width of the rectangles is 6 centimeters. The length of the middle rectangle is 8 centimeters. Two identical triangles adjoin the middle rectangle at the top and bottom with sides each measuring 8 centimeters and the perpendicular height measuring 6.9 centimeters.
What is the surface area of the triangular prism? Round the answer to the nearest tenth.
Give me a correct answer
To find the surface area of the triangular prism, we need to calculate the areas of the individual faces and then add them together.
The triangular prism is made up of two identical triangles and three rectangular faces.
The area of a rectangle can be found by multiplying its length by its width.
Area of each rectangle = 6 cm * 8 cm = 48 cm^2
The area of a triangle can be found by multiplying its base by its height and dividing by 2.
Area of each triangle = (8 cm * 6.9 cm) / 2 = 55.2 cm^2
Since there are two triangles, the total area of the triangular faces is 2 * 55.2 cm^2 = 110.4 cm^2.
The total surface area of the triangular prism is the sum of the areas of the rectangles and triangles: 110.4 cm^2 + 3 * 48 cm^2 = 254.4 cm^2.
Rounding to the nearest tenth, the surface area of the triangular prism is approximately 254.4 cm^2.