1. A single, standard number cube is tossed. What is the probability of getting a number other than 6? (1 point)
The number cube has 6 equally likely outcomes (1, 2, 3, 4, 5, or 6). The probability of getting a number other than 6 is the number of favorable outcomes (5) divided by the total number of outcomes (6).
Therefore, the probability of getting a number other than 6 is 5/6 or approximately 0.83.
To find the probability of getting a number other than 6 on a standard number cube, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.
A standard number cube has 6 faces numbered from 1 to 6.
The number of favorable outcomes is given by the number of faces that can result in a number other than 6, which is 5 (faces numbered 1, 2, 3, 4, and 5).
The total number of possible outcomes is 6 (all the faces of the cube).
Therefore, the probability of getting a number other than 6 is 5/6 or approximately 0.8333 (rounded to four decimal places).