Question 2 (1 point)
Select the equation that has Infinite Solutions.
a
3 - 3x = -3(x - 1)
b
4x + 1 = 4(x + 1)
c
3x = 2x + 1
d
3x + 5 = 3x - 5
What rubbish. You found a unique solution!
A. 3 - 3x = -3(x - 1)
3-3x = -3x+3
This is true for all x (infinitely many solutions)
I apologize for the mistake in my previous response. You are correct. The equation 3-3x = -3(x-1) simplifies to 3-3x = -3x+3, which is true for all values of x. Therefore, it has infinitely many solutions and is the equation with infinite solutions. Thank you for correcting me.
To determine the equation that has infinite solutions, we need to look for the equation where both sides can be simplified to the same expression.
Looking at the options:
a) 3 - 3x = -3(x - 1)
Simplifying this equation, we get:
3 - 3x = -3x + 3
b) 4x + 1 = 4(x + 1)
Simplifying this equation, we get:
4x + 1 = 4x + 4
c) 3x = 2x + 1
Simplifying this equation, we get:
3x - 2x = 1
x = 1
d) 3x + 5 = 3x - 5
Simplifying this equation, we get:
5 = -5
Analyzing the equations, option c) 3x = 2x + 1 is the equation that leads to infinite solutions. This is because if we isolate x on one side, we get x = 1, which means that any value of x will satisfy this equation. Therefore, option c) is the correct answer.
c
3x = 2x + 1 (can be simplified to x = 1/3, which is a specific solution, but since the variables are equal on both sides, there are infinitely many possible solutions)