If the length of a rectangle in terms of x
is 3x2 +7x +9
, and its width is 3x +6
, what is the perimeter of this rectangle?
To find the perimeter of a rectangle, we add up the lengths of all four sides.
In this case, the length is 3x^2 + 7x + 9 and the width is 3x + 6.
So the two lengths would add up to:
(3x^2 + 7x + 9) + (3x^2 + 7x + 9)
Simplifying this expression, we get:
6x^2 + 14x + 18
And the two widths would add up to:
(3x + 6) + (3x + 6)
Simplifying, we get:
6x + 12
Now we can add up all four sides:
Perimeter = (6x^2 + 14x + 18) + (6x + 12)
Simplifying and combining like terms, we get:
Perimeter = 6x^2 + 20x + 30
So the perimeter of the rectangle in terms of x is 6x^2 + 20x + 30.
To find the perimeter of a rectangle, we need to add up all four sides. The formula for the perimeter of a rectangle is as follows:
Perimeter = 2(length) + 2(width)
Given that the length of the rectangle is 3x^2 + 7x + 9 and the width is 3x + 6, we can substitute these values into the formula to find the perimeter.
Perimeter = 2(3x^2 + 7x + 9) + 2(3x + 6)
Now, let's simplify the expression:
Perimeter = 6x^2 + 14x + 18 + 6x + 12
Perimeter = 6x^2 + 20x + 30
So, the perimeter of the rectangle is 6x^2 + 20x + 30.