23.780g of acetaldehyde (CH3CHO) reacts completely with oxygen to produceacetic acid (HC2H3O2) using manganese (II)acaetate catalyst according to the equation shown below:
2CH3CHO + O2 → 2HC2H3O2
What mass of oxygen reacted with acetaldehyde ? (Atomic mass: C-12.011 g/mol; 0-15.999 g/mol; H-
1.008 g/mol).
34.558 g
8.623 g
17.247 g
34.484 g
34.558 g
To find the mass of oxygen that reacted with acetaldehyde, we need to determine the stoichiometry of the reaction.
According to the balanced equation:
2CH3CHO + O2 → 2HC2H3O2
From this equation, we can determine that 2 moles of acetaldehyde react with 1 mole of oxygen.
Step 1: Convert the mass of acetaldehyde to moles.
molar mass of acetaldehyde (CH3CHO) = (12.011 g/mol * 3) + (1.008 g/mol * 4) + (15.999 g/mol) = 44.053 g/mol
moles of acetaldehyde = mass of acetaldehyde / molar mass of acetaldehyde
= 23.780 g / 44.053 g/mol
= 0.5395 mol
Step 2: Use the stoichiometry to determine the moles of oxygen.
moles of oxygen = (moles of acetaldehyde) / 2
= 0.5395 mol / 2
= 0.2697 mol
Step 3: Convert the moles of oxygen to mass.
molar mass of oxygen (O2) = 15.999 g/mol
mass of oxygen = moles of oxygen * molar mass of oxygen
= 0.2697 mol * 15.999 g/mol
= 4.316 g
Therefore, the mass of oxygen that reacted with acetaldehyde is approximately 4.316 g.
None of the given answer choices match the calculated value, so there may be an error in the question or answer choices.
To find the mass of oxygen that reacted with acetaldehyde, we need to use stoichiometry and the balanced chemical equation. Here are the steps to find the answer:
1. Calculate the molar mass of acetaldehyde (CH3CHO).
Molar mass of CH3CHO = (1 x 12.011 g/mol) + (3 x 1.008 g/mol) + 12.011 g/mol + 15.999 g/mol
= 44.053 g/mol
2. Determine the molar ratio between acetaldehyde (CH3CHO) and oxygen (O2) from the balanced chemical equation.
From the equation 2CH3CHO + O2 → 2HC2H3O2, we can see that 2 moles of acetaldehyde react with 1 mole of oxygen.
3. Convert the given mass of acetaldehyde to moles.
Moles of acetaldehyde = Mass of acetaldehyde / Molar mass of acetaldehyde
= 23.780 g / 44.053 g/mol
= 0.539 moles
4. Use the molar ratio to find the number of moles of oxygen used.
Moles of oxygen = Moles of acetaldehyde x (1 mole of O2 / 2 moles of acetaldehyde)
= 0.539 moles x (1 mole of O2 / 2 moles of acetaldehyde)
= 0.2695 moles
5. Convert the moles of oxygen to mass.
Mass of oxygen = Moles of oxygen x Molar mass of oxygen
= 0.2695 moles x 15.999 g/mol
= 4.312 g
Therefore, the mass of oxygen that reacted with acetaldehyde is approximately 4.312 g. None of the provided answer choices match the calculated value, so 34.558 g, 8.623 g, 17.247 g, and 34.484 g are incorrect.