A game involves spinning this spinner. What is the probability of the pointer landing on Y?
A circle is divided equally into eight sections.· Two of the sections are labeled with an upper B.
· One of the sections is labeled with an upper G.
· One of the sections is labeled with an upper Y.
· Four of the sections are labeled with an upper R.
· An arrow originating from the center of the circle is pointing at one of the sections with an upper R. (1 point)
one-eighth
one-half
start fraction 5 over 8 end fraction
two-eighths
The probability of the pointer landing on Y is 1/8.
The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant the first time and a vowel the second time if the spinner is spun twice.
A circle is divided equally into three sections.· One of the sections is labeled with an upper E.
· One of the sections is labeled with an upper U.
· One of the sections is labeled with an upper N.
· An arrow originating from the center of the circle is pointing at the section labeled with upper U. (1 point)
two-thirds
two-ninths
three-fourths
start fraction 5 over 9 end fraction
First, we need to find the probability of landing on a consonant on the first spin. Since two out of the three sections are consonants, the probability is 2/3.
Next, we need to find the probability of landing on a vowel on the second spin, given that we landed on a consonant on the first spin. We can represent this with a branch extending from each possible outcome of the first spin:
```
C V
/ | \ / | \
C V N C V N
```
The probability of landing on a vowel, given that we already landed on a consonant, is 1/2 since there is one vowel and one consonant remaining.
To find the overall probability of landing on a consonant and then a vowel, we multiply the probabilities of each event:
(2/3) x (1/2) = 1/3
Therefore, the probability of the spinner landing on a consonant the first time and a vowel the second time is 1/3.
The probability of the pointer landing on Y can be calculated by finding the ratio of the favorable outcomes (landing on Y) to the total number of possible outcomes.
In this case, there is only one section labeled with an upper Y, and there are a total of eight sections on the spinner.
Therefore, the probability of the pointer landing on Y is:
1/8 or one-eighth.