Find the pH in which the hydrogen ion,H± concentration is 0.395×moldm-³
We can use the formula:
pH = -log[H+]
where [H+] is the hydrogen ion concentration in mol/dm³.
First, let's convert the concentration to mol/dm³:
0.395 × mol/dm³
Next, we can plug this value into the pH formula:
pH = -log (0.395)
Using a calculator, we get:
pH = 0.403
Therefore, the pH at which the hydrogen ion concentration is 0.395 mol/dm³ is approximately 0.403.
To find the pH with a given hydrogen ion concentration, you can use the formula:
pH = -log[H+]
Here, [H+] represents the concentration of the hydrogen ions.
In this case, the hydrogen ion concentration is given as 0.395 × moldm^-3.
To find the pH, substitute the hydrogen ion concentration into the formula:
pH = -log(0.395 × 10^-3)
Calculating this expression gives us:
pH ≈ -log(3.95 × 10^-4)
Using the logarithmic identity, log(a×b) = log(a) + log(b), we can simplify the expression:
pH ≈ -log(3.95) - log(10^-4)
Since log(10^-4) is equal to -4, we have:
pH ≈ -log(3.95) - (-4)
pH ≈ -log(3.95) + 4
Using a scientific calculator or logarithm tables, you can find that log(3.95) is roughly 0.595.
Substituting this value, we get:
pH ≈ -0.595 + 4
pH ≈ 3.405
Therefore, the pH with a hydrogen ion concentration of 0.395 × moldm^-3 is approximately 3.405.