The diameter of the large piston of a hydrolic press is 20 cm,and the cross-sectional area of the small piston is 5cm².if the force of 400N is applied to the small piston,what is the resulting force exerted on the large piston?
We can use the principle of Pascal's Law which states that pressure applied to a fluid is transmitted uniformly in all directions. Therefore, the pressure applied to the small piston will be transmitted to the large piston, resulting in a larger force.
First, we need to find the pressure applied to the small piston:
Pressure = Force/Area
Pressure = 400N/5cm²
Pressure = 80N/cm²
Now, we can use this pressure to find the resulting force on the large piston:
Force = Pressure x Area
Force = 80N/cm² x π(10cm)²
Force = 80N/cm² x 100πcm²
Force = 8000πN
Therefore, the resulting force exerted on the large piston is approximately 25,132 N (8000π ≈ 25,132).