The ages, in years, of randomly selected employees are 34, 41, 28, 35, 27, 44, 48, 29, 33, and 39. Determine the mean age.(1 point)

Responses

37.8
37.8

39.8
39.8

36.8
36.8

35.8

To determine the mean age, you need to calculate the sum of all the ages and divide it by the total number of employees. Here's how to do it:

1. Add up all the ages: 34 + 41 + 28 + 35 + 27 + 44 + 48 + 29 + 33 + 39 = 358.
2. Count the total number of employees, which in this case is 10.
3. Divide the sum of ages (358) by the total number of employees (10): 358 / 10 = 35.8.

Therefore, the mean age is 35.8.

The correct answer is 2.14 hours.

To find the mean number of hours students spent on math homework, you need to multiply each data point (number of hours x number of students) and then add them up. Divide the total by the number of students (which is the sum of the number of students for each data point):

(1 x 8) + (2 x 6) + (3 x 4) + (4 x 2) + (5 x 1) = 8 + 12 + 12 + 8 + 5 = 45

The sum of the number of students for each data point is: 8 + 6 + 4 + 2 + 1 = 21

Therefore, the mean number of hours students spent on math homework is:

45/21 ≈ 2.14 hours

The false statement is:

Both fast food restaurants have exactly one modal delivery time of 40 minutes.

To find the mode(s), you need to identify the value(s) that appears most frequently. In this case, for Fast Food 1, the mode is 38 and for Fast Food 2, the modes are 37 and 40.

Therefore, the statement that both restaurants have exactly one modal delivery time of 40 minutes is false.

The correct answer is 37.8.

To find the mean age, you need to add up all of the ages and divide by the total number of employees:

(34 + 41 + 28 + 35 + 27 + 44 + 48 + 29 + 33 + 39) / 10 = 378 / 10 = 37.8

Use the image to answer the question.

A bar graph shows the number of hours spent on math homework versus the number of students. The horizontal axis shows the time in hours ranging from 1 to 5 in increments of 1. The vertical axis shows the number of students ranging from 0 to 10 in increments of 1. The data with time in hours, followed by the number of students is as follows: 1 to 8, 2 to 6, 3 to 4, 4 to 2, and 5 to 1.

The graph shows the number of hours randomly selected students spent on math homework. What is the mean number of hours students spent on math homework?

(1 point)
Responses

1 hour
1 hour

2.14 hours
2.14 hours

1.4 hours
1.4 hours

9 hours
9 hours

For 10 consecutive days, Anthony recorded the daily high temperatures in Dayton and Laredo. The table shows the data.

Daily High Temperatures (in °F)
Dayton 77 82 85 87 90 85 79 86 91 88
Laredo 81 79 80 86 88 92 82 88 84 87
Which city has a higher median daily high temperature? How much higher is this city’s median than the other city’s median daily high temperature?

(1 point)
Responses

Dayton has a higher median daily high temperature than Laredo by 0.5°F.
Dayton has a higher median daily high temperature than Laredo by , 0.5 degree , F.

Dayton has a higher median daily high temperature than Laredo by 0.3°F.
Dayton has a higher median daily high temperature than Laredo by , 0.3 degree , F.

Laredo has a higher median daily high temperature than Dayton by 0.5°F.
Laredo has a higher median daily high temperature than Dayton by , 0.5 degree , F.

Laredo has a higher median daily high temperature than Dayton by 1°F.

The following data set represents the highway fuel efficiency in miles per gallon (mpg) of randomly selected cars from two car companies.

Car Company A: 35, 28, 35, 30, 31, 38, 35, 30
Car Company B: 29, 33, 36, 27, 34, 34, 34, 25

Which of the following statements is true?

(1 point)
Responses

The cars from both companies have the same mean, median, and modal highway fuel efficiency.
The cars from both companies have the same mean, median, and modal highway fuel efficiency.

The cars from Company A have higher median highway fuel efficiency than Company B.
The cars from Company A have higher median highway fuel efficiency than Company B.

The cars from Company B have higher modal highway fuel efficiency than Company A.
The cars from Company B have higher modal highway fuel efficiency than Company A.

The cars from Company A have a higher mean highway fuel efficiency that Company B.
The cars from Company A have a higher mean highway fuel efficiency that Company B.

The correct answer is:

The cars from Company A have a higher mean highway fuel efficiency than Company B.

To find the mean fuel efficiency for each company, you need to add up all the values and divide by the total number of cars:

For Company A: (35 + 28 + 35 + 30 + 31 + 38 + 35 + 30) / 8 = 262 / 8 = 32.75 mpg
For Company B: (29 + 33 + 36 + 27 + 34 + 34 + 34 + 25) / 8 = 252 / 8 = 31.5 mpg

Therefore, Company A has a higher mean fuel efficiency than Company B.

To find the median, you need to rearrange the values in order and find the middle value. For Company A, the median is 35 while for Company B the median is 33.5. So, the statement that the companies have the same median is false.

To find the mode, you need to find the value that appears most frequently. For both companies, the mode is 35. So, the statement that Company B has a higher modal fuel efficiency is false.

Therefore, the only true statement is that the cars from Company A have a higher mean fuel efficiency than Company B.

Measures of Center Quick Check

5 of 55 of 5 Items

Question
The randomly selected delivery times (in minutes) of two fast food restaurants are as follows.

Fast Food 1 Fast Food 2
42 40
38 37
37 40
39 41
38 38
40 46
45 41
41 37
40 40
Which of the following statements is false?

(1 point)
Responses

Neither data set contains an outlier.
Neither data set contains an outlier.

Both fast food restaurants have the same median delivery time of 40 minutes.
Both fast food restaurants have the same median delivery time of 40 minutes.

Both fast food restaurants have exactly one modal delivery time of 40 minutes.
Both fast food restaurants have exactly one modal delivery time of 40 minutes.

Both fast food restaurants have the same mean delivery time of 40 minutes.
Both fast food restaurants have the same mean delivery time of 40 minutes.

To determine which city has a higher median daily high temperature, you need to rearrange each city's temperatures from lowest to highest and then find the middle value (or the average of the two middle values if there is an even number of temperatures).

For Dayton: 77 79 82 85 85 86 87 88 90 91
The median is the middle value, which is 86.

For Laredo: 79 80 81 82 84 86 87 88 88 92
The median is also 86.

Therefore, both cities have the same median daily high temperature.

The correct answer is not provided in the options given.