what is the slope of the line tangent to the function f(x)=7x^2+1 at x=-2?
To find the slope of the line tangent to the function at x = -2, we need to take the derivative of the function first.
f(x) = 7x^2 +1
f'(x) = 14x
Next, we substitute x = -2 into f'(x):
f'(-2) = 14(-2) = -28
Therefore, the slope of the line tangent to the function f(x) = 7x^2 + 1 at x = -2 is -28.