Subtract.
Start Fraction 5 over t squared End Fraction minus Start Fraction 4 over t plus 1 End Fraction
A. start fraction 5 t plus 2 over t squared times left parenthesis t plus 1 right parenthesis end fraction
B. start fraction 5 t plus 1 minus 4 t squared over t squared times left parenthesis t plus 1 right parenthesis end fraction
C. start fraction 1 over t squared times left parenthesis t plus 1 right parenthesis end fraction
D. start fraction 5 plus 5 t minus 4 t squared over t squared times left parenthesis t plus 1 right parenthesis end fraction
B. start fraction 5 t plus 1 minus 4 t squared over t squared times left parenthesis t plus 1 right parenthesis end fraction
AAAaannndd the bot gets it wrong yet again!
Start Fraction 5 over t squared End Fraction minus Start Fraction 4 over t plus 1 End Fraction
5/t^2 - 4/(t+1)
= (5(t+1) - 4t^2)/(t^2(t+1))
= (-4t^2+5t+5)/(t^2(t+1))
so D
. start fraction 5 + 5 t - 4 t squared over t squared times left parenthesis t + 1 right parenthesis end fraction is the correct answer. Thank you for catching the mistake!
To subtract the given fractions, we need to find a common denominator. In this case, the common denominator is t^2 * (t + 1).
The first fraction, 5/t^2, needs to be multiplied by (t + 1)/(t + 1). This gives us (5 * (t + 1))/(t^2 * (t + 1)).
The second fraction, 4/(t + 1), needs to be multiplied by t^2/t^2. This gives us (4t^2)/(t^2 * (t + 1)).
Now, we can subtract the fractions:
(5 * (t + 1))/(t^2 * (t + 1)) - (4t^2)/(t^2 * (t + 1))
Combining the fractions over a common denominator, we get:
(5t + 5 - 4t^2)/(t^2 * (t + 1))
So, the answer is D. Start Fraction 5 + 5t - 4t^2 End Fraction / t^2(t + 1).