write the equation in standard form for the circle with center (-6,-3) and radius 4
The standard form equation for a circle with center (h,k) and radius r is:
(x - h)^2 + (y - k)^2 = r^2
Substituting the given values:
(x - (-6))^2 + (y - (-3))^2 = 4^2
Simplifying:
(x + 6)^2 + (y + 3)^2 = 16
Therefore, the equation in standard form for the circle with center (-6,-3) and radius 4 is (x + 6)^2 + (y + 3)^2 = 16.