On a map, the distance between Milvale and Dracut is 114 inches. If the map uses a scale of 14 inch represents 1 mile, what is the actual distance in miles from Milvale to Dracut?
To solve the problem, we need to use the scale provided in the question:
14 inches represents 1 mile
We can set up a proportion:
14 inches / 1 mile = 114 inches / x miles
where x is the actual distance in miles from Milvale to Dracut.
To solve for x, we can cross-multiply:
14 inches * x miles = 1 mile * 114 inches
Simplifying the right side:
114 inches = 114/1 inches = 114 miles / 14
Multiplying both sides by 14:
14 inches * x miles = (114 miles / 14) * 14 inches
Simplifying the right side:
14 inches * x miles = 114 miles
Dividing both sides by 14 inches:
x miles = 114 miles / 14 inches
x miles = 8.14 miles
Therefore, the actual distance in miles from Milvale to Dracut is 8.14 miles.
A food company reduced the amount of salt in one of their food products from 700 milligrams to 630 milligrams. What is the percent decrease in the amount of salt in this food product?
To find the percent decrease, we need to calculate the difference between the original amount of salt and the new amount of salt, divide that by the original amount, and then multiply by 100 to express the result as a percentage.
The difference between the original amount and the new amount is:
700 milligrams - 630 milligrams = 70 milligrams
To find the percentage decrease, we divide this difference by the original amount:
70 milligrams / 700 milligrams = 0.1
Multiplying by 100, we get:
0.1 * 100 = 10%
Therefore, the percent decrease in the amount of salt in the food product is 10%.
To find the actual distance in miles from Milvale to Dracut, you need to use the given scale.
The scale tells you that 14 inches on the map represents 1 mile in real life. Therefore, you can set up a proportion to solve for the actual distance:
Distance on the map (in inches) / Scale = Actual distance (in miles)
Let's represent the actual distance as 'x' miles. Plugging in the given values, we have:
114 inches / 14 inches = x miles
Now, we can solve for 'x':
114 / 14 = x
8.14 = x
Therefore, the actual distance from Milvale to Dracut is approximately 8.14 miles.