The second and fifth term of a geometric progression are 1 and⅛ respectively find the first term
Let the first term be $a$ and the common ratio be $r$. Then we have:
Second term: $ar$
Fifth term: $ar^4$
It is given that:
$ar=1$
$ar^4=\dfrac{1}{8}$
Dividing the second equation by the first, we get:
$r^3=\dfrac{1}{8}$
$r=\dfrac{1}{2}$
Substituting this value of $r$ in the first equation, we get:
$a(\dfrac{1}{2})=1$
$a=2$
Therefore, the first term is $\boxed{2}$.