What are the x-intercepts of this function?
f (x) = 4x^2-9
To find the x-intercepts, we need to set f(x) equal to zero and solve for x:
4x^2 - 9 = 0
We can factor this equation as:
(2x + 3)(2x - 3) = 0
Using the zero product property, we can set each factor equal to zero and solve for x:
2x + 3 = 0 or 2x - 3 = 0
Solving for x, we get:
x = -3/2 or x = 3/2
Therefore, the x-intercepts of the function are (-3/2, 0) and (3/2, 0).