The area of a trapezoid is 21 cm2. The bases are 3 cm and 4 cm. What is the height of the trapezoid?
Question 28 options:
1)
7 cm
2)
14 cm
3)
6 cm
4)
12 cm
Option 3) 6 cm.
The formula for the area of a trapezoid is A = (1/2)(b1 + b2)h, where b1 and b2 are the lengths of the bases and h is the height. We are given A = 21 cm2, b1 = 3 cm, and b2 = 4 cm. Plugging these values into the formula, we get:
21 = (1/2)(3 + 4)h
21 = (1/2)(7)h
21 = 3.5h
h = 21/3.5
h = 6
Therefore, the height of the trapezoid is 6 cm.
What is the area of a trapezoid with a base of 4 inches, the other base of 6 inches, and a height of 7 inches?
The area of a trapezoid is given by the formula:
A = (1/2)(b1 + b2)h
where b1 and b2 are the lengths of the bases, and h is the height. Plugging in the given values, we get:
A = (1/2)(4 + 6)(7)
A = (1/2)(10)(7)
A = 35
Therefore, the area of the trapezoid is 35 square inches.
To find the height of a trapezoid, you can use the formula:
Area = ((a + b) * h) / 2
where 'a' and 'b' are the lengths of the bases and 'h' is the height of the trapezoid.
Given that the area of the trapezoid is 21 cm^2 and the bases are 3 cm and 4 cm, we can substitute these values into the formula and solve for 'h'.
Using the formula:
21 = ((3 + 4) * h) / 2
First, simplify the equation:
21 = (7h) / 2
Multiply both sides of the equation by 2 to get rid of the denominator:
42 = 7h
Now, divide both sides of the equation by 7 to isolate 'h':
h = 42 / 7
Simplifying further:
h = 6 cm
Therefore, the height of the trapezoid is 6 cm. So, the correct answer is option 3) 6 cm.