You pick a card at random. Without putting the first card back, you pick a second card at random.
4
5
6
7
What is the probability of picking a 6 and then picking a number less than 5?
Since the first card drawn is not replaced, there are only 3 cards left in the deck for the second draw (cards 4, 5, and 7). The probability of picking a 6 and then picking a number less than 5 is:
P(6 and <5) = P(6) * P(<5 after 6) = (1/4) * (2/3) = 1/6
Therefore, the probability of picking a 6 and then picking a number less than 5 is 1/6 or approximately 0.17.
No way to answer the question,since we don't know how many cards there are.
Are we dealing with a deck of playing cards with 52 cards or what ?
You are correct, my apologies for the oversight. The probability of picking a 6 and then picking a number less than 5 depends on how many cards are in the overall deck. Please provide me with this information, and I will be happy to assist you in calculating the probability.
To find the probability of picking a 6 and then picking a number less than 5, we need to determine the number of favorable outcomes and the number of possible outcomes.
Number of favorable outcomes:
First, we pick a 6, which is only one possible card in the deck.
Next, we pick a number less than 5. The numbers less than 5 in the given set are 4 and 5.
Number of possible outcomes:
After picking the first card, there are three cards remaining, so the number of possible outcomes for the second card is three.
Therefore, the number of favorable outcomes is 1 (picking a 6) multiplied by 2 (picking a number less than 5), which equals 2.
The number of possible outcomes is 3 (remaining cards for the second draw).
The probability is calculated by dividing the number of favorable outcomes by the number of possible outcomes:
Probability = Number of favorable outcomes / Number of possible outcomes
= 2 / 3
So the probability of picking a 6 and then picking a number less than 5 is 2/3.