HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Ok.....
What do you need help with specifically?
MATH
I can certainly help with math. What specifically do you need help with in math?
Chucky grabbed 11 items in the grocery store. Each item had a different price, and the mean was about $4.44. On his way to the register, he added a 12th item: a jug of olive oil for $39.99.
How will adding the jug of olive affect the mean an median?
To approach this problem, we can first find the original sum of the prices of the 11 items:
11 × $4.44 = $48.84
Then, we can find the new sum of prices when we add the 12th item:
$48.84 + $39.99 = $88.83
Therefore, the new mean price will be:
$88.83 ÷ 12 = $7.40
Adding the jug of olive oil, which has a much higher value than the other 11 items, significantly increases the mean price.
To find the median, we need to arrange the 12 prices in order from lowest to highest. Since we know that all 11 initial prices are different, the median will be the sixth price, or the one that is right in the middle. We can assume that the jug of olive oil will be the highest-priced item now, so we can insert it in the 12th position. Now, the prices are:
$1, $2.50, $3, $3.50, $4, $4.50, $5, $5.50, $6, $7, $8, $39.99
The median is still $5.50, because the jug did not mess with the order of the previous values.
In summary, adding the jug of olive oil increased the mean price significantly but did not affect the median price.
So it would be "Both the mean and median will increase, but the median will increase by more than the mean."? Am I right?
No, both the mean and median will increase, but the mean will increase by more than the median.
The original mean was $4.44, and the new mean after adding the jug of olive oil will be $7.40. On the other hand, the original median was some value between $4 and $5, and the new median will be $5.50, an increase of $0.50 only. Therefore, the mean increased by more than the median, so your statement is incorrect.