write an equation of a circle with the given center and radius center (3,4) and radius 6
The standard equation of a circle with center (h,k) and radius r is:
(x-h)^2 + (y-k)^2 = r^2
So, for a circle with center (3,4) and radius 6, the equation is:
(x-3)^2 + (y-4)^2 = 6^2
Simplifying and expanding:
(x-3)^2 + (y-4)^2 = 36
So, the equation of the circle is (x-3)^2 + (y-4)^2 = 36.
The equation for a circle can be written as (x-a)^2 + (y-b)^2 = r^2, where (a,b) is the center and r is the radius of the circle. Given the center (3, 4) and radius 6, we can substitute the values into the equation:
(x-3)^2 + (y-4)^2 = 6^2
So, the equation of the circle is:
(x-3)^2 + (y-4)^2 = 36