Use the figure to answer the question.

Question

Use the figure to answer the question.

Information
A figure.Short description, A figure.,Long description,
The closed figure has 6 straight sides. The figure looks like a tall rectangle with a smaller rectangle attached on the bottom right.

The left vertical length is 16 meters.
The right vertical lengths are 14 meters for the tall rectangle and 2 meters for the smaller rectangle.
The top horizontal length is 8 meters.
The middle horizontal length that is the top of the smaller rectangle is 4 meters.
The bottom horizontal length is 12 meters.

Question
What is the area of figure?

Answer options with 5 options
A.
56 square meters

B.
80 square meters

C.
120 square meters

D.
136 square meters

E.
152 square meters

Answer 1

D. 136 square meters

Answer 2

Angles A O B and B O C are adjacent. Angle A O C measures 118 degrees and angle A O B measures 46 degrees.

A diagram shows that angle A O C has vector O B that forms adjacent angles A O B and B O C.

Question 1
,begin emphasis,Part A,end emphasis,
Which equation can be used to find the measure of angle B O C?

Question 1 Answer options with 4 options
A.
46x equals 118

B.
46 plus 118 equals x

C.
46 plus x equals 118

D.
x plus 118 equals 46

Question 2
,begin emphasis,Part B,end emphasis,
What is the measure of angle B O C? Enter the answer in the box.

Question 2 Response area with 1 text input box
degrees

Answer 3

Question 1: C. 46 plus x equals 118

Question 2: 72 degrees (calculated by subtracting 46 from 118)

Answer 4

To find the area of the figure, we need to break it down into its individual shapes.

First, let's calculate the area of the tall rectangle. The formula for the area of a rectangle is length times width. In this case, the length is the left vertical length, which is 16 meters, and the width is the top horizontal length, which is 8 meters. So, the area of the tall rectangle is 16 meters times 8 meters, which equals 128 square meters.

Next, let's calculate the area of the smaller rectangle. Its length is the right vertical length of 2 meters, and its width is the middle horizontal length of 4 meters. Therefore, the area of the smaller rectangle is 2 meters times 4 meters, which equals 8 square meters.

Now, we need to find the area of the triangle formed by the two rectangles. To do this, we first need to find the height of the triangle. The height is the difference between the left vertical length (16 meters) and the sum of the right vertical lengths (14 + 2 = 16 meters). Therefore, the height of the triangle is 16 - 16 = 0 meters.

Since the height of the triangle is zero, the area of the triangle is also zero.

Finally, we can find the total area of the figure by adding up the areas of the rectangles. The total area is 128 square meters (for the tall rectangle) + 8 square meters (for the smaller rectangle) + 0 square meters (for the triangle) = 136 square meters.

Therefore, the correct answer is:

D. 136 square meters.