If the specific heat of water is 4.180 J/ g °C, what mass of water can be heated from 5.0°C to 80.0°C by 27000 J of heat?
We can use the formula:
Q = m * c * ΔT
where Q is the heat energy transferred, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
We are given Q = 27000 J, c = 4.180 J/ g °C, ΔT = (80.0°C - 5.0°C) = 75.0°C.
Substituting these values into the formula, we can solve for m:
27000 J = m * 4.180 J/ g °C * 75.0°C
m = 27000 J / (4.180 J/ g °C * 75.0°C)
m = 90.4 g
Therefore, a mass of 90.4 g of water can be heated from 5.0°C to 80.0°C by 27000 J of heat.
A piece of silver releases 202.8 J of heat while cooling 65.0? °C. What is the mass
of the sample? Silver has a specific heat of 0.240 J/g? °C
We can use the formula:
Q = m * c * ΔT
where Q is the heat energy transferred, m is the mass of the silver sample, c is the specific heat capacity of silver, and ΔT is the temperature change.
We are given Q = 202.8 J, c = 0.240 J/g °C, and ΔT = 65.0°C.
Substituting these values into the formula, we can solve for m:
202.8 J = m * 0.240 J/g °C * 65.0°C
m = 202.8 J / (0.240 J/g °C * 65.0°C)
m = 13.45 g
Therefore, the mass of the silver sample is 13.45 g.
To find the mass of water that can be heated, we need to use the formula:
q = m * c * ΔT
Where:
q is the heat energy transferred
m is the mass of the substance
c is the specific heat capacity of the substance
ΔT is the change in temperature
In this case, we know that the specific heat of water is 4.180 J/g °C, the initial temperature is 5.0°C, the final temperature is 80.0°C, and the heat energy transferred is 27000 J. We can rearrange the formula to solve for the mass (m):
m = q / (c * ΔT)
Plugging in the values, we get:
m = 27000 J / (4.180 J/g °C * (80.0°C - 5.0°C))
First, let's calculate the change in temperature:
ΔT = 80.0°C - 5.0°C = 75.0°C
Now we'll substitute the values into the equation:
m = 27000 J / (4.180 J/g °C * 75.0°C)
m = 27000 J / 313.5 J/g
m ≈ 86.14 g
Therefore, the mass of water that can be heated from 5.0°C to 80.0°C by 27000 J of heat is approximately 86.14 grams.