10x + 3y = -11 8x + 2y = -6

To solve the system of equations, we can use either substitution or elimination.

Using substitution:

Solve one of the equations for one of the variables:

10x + 3y = -11
3y = -10x - 11
y = (-10/3)x - 11/3

Substitute this expression for y into the other equation and solve for x:

8x + 2y = -6
8x + 2((-10/3)x - 11/3) = -6
8x - (20/3)x - 22/3 = -6
(24/3)x - (20/3)x = -6 + 22/3
(4/3)x = -4/3
x = -1

Substitute this value of x back into one of the original equations and solve for y:

10x + 3y = -11
10(-1) + 3y = -11
-10 + 3y = -11
3y = -1
y = -1/3

Therefore, the solution to the system of equations is (x,y) = (-1,-1/3).

Using elimination:

Multiply the first equation by -2:

-20x - 6y = 22

Add this to the second equation:

8x + 2y = -6
-20x - 6y = 22
-----------------
-12x = 16

Divide both sides by -12:

x = -4/3

Substitute this value of x into one of the equations and solve for y:

10x + 3y = -11
10(-4/3) + 3y = -11
-40/3 + 3y = -11
3y = -11 + 40/3
3y = -1/3
y = -1/9

Therefore, the solution to the system of equations is (x,y) = (-4/3,-1/9).