how many real number solutions does the equation have? 0=3x^2-5x-5
The equation 0=3x^2-5x-5 is a quadratic equation, so it can be solved using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
where a = 3, b = -5, and c = -5. Plugging these values into the formula, we get:
x = (5 ± √(25 + 60)) / 6
x = (5 ± √85) / 6
These are two distinct real solutions, so the equation has 2 real number solutions.