The equation of a straight line l1 is 3y+4x=12.Find the gradient of l1.
To find the gradient of a straight line, we need to rearrange the equation into the form y = mx + c, where m is the gradient.
3y + 4x = 12
3y = -4x + 12
y = (-4/3)x + 4
The gradient of this line is -4/3.