You roll a number cube twice. Find P (even,then not 2) write the probability as a fraction in simplest form. PLS HELP I DON'T UNDERSTAND THIS QUESTION
There are six possible outcomes when rolling a number cube: 1, 2, 3, 4, 5, or 6. Since we're interested in the probability of rolling an even number on the first roll, we can have outcomes 2, 4, or 6. The probability of rolling an even number is 3/6 or 1/2.
After the first roll, we need to find the probability of rolling a number that is not 2. This leaves four possible outcomes: 1, 3, 4, 5. The probability of rolling any one of these outcomes is 4/6 or 2/3.
To find the probability of both events happening (rolling an even number first and then a number that is not 2), we multiply the two probabilities:
P(even, then not 2) = P(even) * P(not 2)
= (1/2) * (2/3)
= 1/3
Therefore, the probability of rolling an even number on the first roll and then a number that is not 2 on the second roll is 1/3.