A basket contains the following pieces of fruit: 3 apples, 2 oranges, 2 bananas, 2 pears, and 5 peaches. Jameson picks a fruit at random and does not replace it. Then Brittany picks a fruit at random. What is the probability that Jameson gets a banana and Brittany gets a pear?
A. 4/27
B. 1/49
C. 2/91
D. 27/91***
The probability that Jameson selects a banana is 2/14 or 1/7, since there are 2 bananas out of 14 total fruits. After Jameson selects a fruit, there will be 13 fruits remaining, including 2 pears. Therefore, the probability that Brittany selects a pear given that Jameson selected a banana is 2/13.
The probability of both events happening together is the product of their individual probabilities:
(1/7) * (2/13) = 2/91.
Therefore, the answer is C.