x2 − 3x + 4 = 0

This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -3, and c = 4. To solve for x, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

Plugging in the values, we get:

x = (3 ± √((-3)² - 4(1)(4))) / 2(1)

x = (3 ± √(9 - 16)) / 2

x = (3 ± √(-7)) / 2

Since the discriminant (the value inside the square root) is negative, there are no real solutions for this equation. However, there are two complex solutions:

x = (3 + √(-7)) / 2 and x = (3 - √(-7)) / 2

In general form:

x = (3 + i√7) / 2 and x = (3 - i√7) / 2

where "i" represents the imaginary unit (i.e., √(-1)).