y = x2 – 4; y = x – 2

To find the intersection points, we need to solve the system of equations:

y = x^2 - 4
y = x - 2

Since y is equal in both equations, we can set them equal to each other:

x^2 - 4 = x - 2

Now, we want to solve for x:

x^2 - x - 2 = 0

This is a quadratic equation, so we can try to factor it.

(x - 2)(x + 1) = 0

This gives us two possible solutions for x:

x - 2 = 0 => x = 2
x + 1 = 0 => x = -1

Now, we can plug these solutions back into either of the original equations to find the corresponding y values.

For x=2:

y = (2)^2 - 4
y = 4 - 4
y = 0

For x=-1:

y = (-1)^2 - 4
y = 1 - 4
y = -3

Thus, the intersection points of the two curves are:

(2, 0) and (-1, -3)