Which of the numbers 1, 2, and 3 is a solution of 2x+1≥7?(1 point)
To test which numbers are solutions, we can substitute them into the inequality and see if it is true.
If x = 1:
2(1) + 1 ≥ 7
2 + 1 ≥ 7
3 is not greater than or equal to 7, so 1 is not a solution.
If x = 2:
2(2) + 1 ≥ 7
4 + 1 ≥ 7
5 is not greater than or equal to 7, so 2 is not a solution.
If x = 3:
2(3) + 1 ≥ 7
6 + 1 ≥ 7
7 is greater than or equal to 7, so 3 is a solution.
Therefore, the answer is 3.
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To determine which of the numbers 1, 2, and 3 is a solution to the inequality 2x + 1 ≥ 7, we can substitute each number into the inequality and check if the resulting equation is true.
First, let's substitute 1 into the inequality:
2(1) + 1 ≥ 7
2 + 1 ≥ 7
3 ≥ 7
Since 3 is not greater than or equal to 7, 1 is not a solution to the inequality.
Next, let's substitute 2 into the inequality:
2(2) + 1 ≥ 7
4 + 1 ≥ 7
5 ≥ 7
Again, 5 is not greater than or equal to 7, so 2 is not a solution to the inequality.
Finally, substituting 3 into the inequality:
2(3) + 1 ≥ 7
6 + 1 ≥ 7
7 ≥ 7
Since 7 is indeed greater than or equal to 7, 3 is a solution to the inequality.
The solution is: 3
To find which of the numbers 1, 2, and 3 is a solution of the inequality 2x + 1 ≥ 7, we can substitute each of those values into the inequality and check if it holds true.
Let's start with 1:
When we substitute x = 1 into the inequality:
2(1) + 1 ≥ 7
2 + 1 ≥ 7
3 ≥ 7
Since 3 is not greater than or equal to 7, the inequality does not hold true for x = 1.
Now let's try 2:
When we substitute x = 2 into the inequality:
2(2) + 1 ≥ 7
4 + 1 ≥ 7
5 ≥ 7
Again, 5 is not greater than or equal to 7, so the inequality does not hold true for x = 2.
Finally, let's try 3:
When we substitute x = 3 into the inequality:
2(3) + 1 ≥ 7
6 + 1 ≥ 7
7 ≥ 7
Since 7 is equal to 7, the inequality holds true for x = 3.
Therefore, the only solution among the numbers 1, 2, and 3 for the inequality 2x + 1 ≥ 7 is x = 3.