Write 0.4x+0.2y=0.6 in slope-intercept form.(1 point)
y=
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form (y = mx + b), you need to isolate the variable y.
1. Start by moving the 0.4x term to the other side of the equation:
0.2y = -0.4x + 0.6
2. Divide the entire equation by 0.2 to isolate y:
(0.2y)/0.2 = (-0.4x + 0.6)/0.2
Simplifying further:
y = -2x + 3
Therefore, the equation 0.4x + 0.2y = 0.6 can be written in slope-intercept form as y = -2x + 3.
-2x+3
Well, let's see if we can convert the equation into slope-intercept form. We have 0.4x + 0.2y = 0.6.
First, let's isolate the y term by subtracting 0.4x from both sides:
0.2y = -0.4x + 0.6
Next, let's divide both sides of the equation by 0.2 to solve for y:
y = (-0.4/0.2)x + (0.6/0.2)
Simplifying a bit further:
y = -2x + 3
So, the equation 0.4x + 0.2y = 0.6 in slope-intercept form is y = -2x + 3.
To write the equation 0.4x + 0.2y = 0.6 in slope-intercept form, we need to isolate y on one side of the equation.
First, let's move the 0.4x term to the other side of the equation by subtracting 0.4x from both sides:
0.4x + 0.2y - 0.4x = 0.6 - 0.4x
Simplifying, we have:
0.2y = 0.6 - 0.4x
Next, we can simplify the right side of the equation further:
0.2y = -0.4x + 0.6
Now, divide the entire equation by 0.2 to isolate y:
(0.2y)/0.2 = (-0.4x + 0.6)/0.2
Simplifying, we have:
y = -2x + 3
Therefore, the equation 0.4x + 0.2y = 0.6 is written in slope-intercept form as y = -2x + 3.