75 kg man walking at 1.0 m/s.

What is the kinetic energy of the man?

The kinetic energy (KE) of an object is given by the equation KE = 1/2mv^2, where m is the mass of the object and v is the velocity.

Substituting the given values, we get:

KE = 1/2(75 kg)(1.0 m/s)^2
KE = 37.5 joules

Therefore, the kinetic energy of the man is 37.5 joules.