A spectrum of lead shows an intense line of 283.3. Calculate the frequency
We can use the formula:
c = λν
where c is the speed of light (h = 2.998 x 10^8 m/s), λ is the wavelength in meters, and ν is the frequency in Hertz.
First, we need to convert the wavelength from nanometers (nm) to meters:
λ = 283.3 nm = 283.3 x 10^-9 m
Now we can plug in the values and solve for ν:
c = λν
ν = c/λ
ν = (2.998 x 10^8 m/s) / (283.3 x 10^-9 m)
ν = 1.06 x 10^15 Hz
Therefore, the frequency of the intense line of lead is 1.06 x 10^15 Hz.
To calculate the frequency of the intense line at 283.3 in the spectrum of lead, we need to make use of the equation that relates frequency and wavelength.
The equation is given as follows:
frequency (ν) = speed of light (c) / wavelength (λ)
The speed of light, denoted by "c", is a constant value, approximately equal to 3 x 10^8 meters per second (m/s).
To find the frequency, we first need to determine the wavelength of the intense line at 283.3. The wavelength, denoted by "λ", is usually given in units such as meters, centimeters, or nanometers.
Assuming the wavelength is given in nanometers (nm), you can directly use the equation to calculate the frequency:
frequency (ν) = 3 x 10^8 m/s / (wavelength in nm)
Substituting the given wavelength of 283.3 nm into the equation:
frequency (ν) = 3 x 10^8 m/s / 283.3 nm
Calculating this, we get:
frequency (ν) ≈ 1.06 x 10^15 Hz
So, the frequency of the intense line at 283.3 in the spectrum of lead is approximately 1.06 x 10^15 Hertz (Hz).
To calculate the frequency of the intense line of 283.3 in the spectrum of lead, you can use the equation:
frequency = speed of light / wavelength
First, we need to convert the wavelength from nanometers to meters since the speed of light is usually given in meters per second.
1 nm = 1 x 10^-9 m
Therefore, the wavelength of 283.3 nm can be expressed as:
283.3 nm = 283.3 x 10^-9 m
Next, we need to determine the speed of light, which is approximately:
speed of light = 3 x 10^8 m/s
Now we can substitute the values into the equation:
frequency = (3 x 10^8 m/s) / (283.3 x 10^-9 m)
Simplifying the equation, we get:
frequency ≈ 1.061 x 10^15 Hz
Therefore, the frequency of the intense line at 283.3 in the spectrum of lead is approximately 1.061 x 10^15 Hz.