2.54g of sodium chloride were dissolved in water and the solution made up to 100cm cube. What is the concentration of the solution in mole per decimeter cube?
First, we need to find the number of moles of sodium chloride (NaCl) present in 2.54 grams.
Molar mass of NaCl = 58.44 g/mol (23g for sodium + 35.44g for chlorine)
Number of moles = mass / molar mass
Number of moles = 2.54 g / 58.44 g/mol = 0.0435 mol (rounded to 4 decimal places)
Now, we need to find the volume of the solution in cubic decimeters (dm³).
Given that the solution was made up to 100 cm³, we have:
1 dm³ = 1000 cm³
100 cm³ = 0.1 dm³
Now, we can find the concentration in moles per cubic decimeter (mol/dm³):
Concentration = number of moles / volume
Concentration = 0.0435 mol / 0.1 dm³ = 0.435 mol/dm³
So, the concentration of the solution is 0.435 mol/dm³.