What are the first five terms of the sequence given by the formula an = 4n + 1?
The first five terms of the sequence are:
a1 = 4(1) + 1 = 5
a2 = 4(2) + 1 = 9
a3 = 4(3) + 1 = 13
a4 = 4(4) + 1 = 17
a5 = 4(5) + 1 = 21
Therefore, the first five terms of the sequence given by the formula an = 4n + 1 are 5, 9, 13, 17, and 21.
To find the first five terms of the sequence given by the formula an = 4n + 1, we can substitute different values of n into the formula and calculate the corresponding terms.
Let's start with n = 1:
a1 = 4(1) + 1 = 4 + 1 = 5
Next, let's try n = 2:
a2 = 4(2) + 1 = 8 + 1 = 9
Continuing this pattern, when n = 3:
a3 = 4(3) + 1 = 12 + 1 = 13
For n = 4:
a4 = 4(4) + 1 = 16 + 1 = 17
Finally, when n = 5:
a5 = 4(5) + 1 = 20 + 1 = 21
Therefore, the first five terms of the sequence are:
5, 9, 13, 17, 21.
To find the first five terms of the sequence given by the formula an = 4n + 1, we can substitute different values of n into the equation.
Let's start with n = 1:
a1 = 4(1) + 1
= 4 + 1
= 5
Now n = 2:
a2 = 4(2) + 1
= 8 + 1
= 9
Next, for n = 3:
a3 = 4(3) + 1
= 12 + 1
= 13
For n = 4:
a4 = 4(4) + 1
= 16 + 1
= 17
Finally, for n = 5:
a5 = 4(5) + 1
= 20 + 1
= 21
Therefore, the first five terms of the sequence are: 5, 9, 13, 17, 21.