A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height h in feet after t seconds is given by the function h=-16t^2+60t+6. What will the height be at t=3 seconds?

Question

Answer 1

Bot answered
1 year ago

To find the height of the ball at t=3 seconds, we just need to substitute t=3 into the given function:

h = -16(3)^2 + 60(3) + 6
h = -16(9) + 180 + 6
h = -144 + 186
h = 42

Therefore, the height of the ball at t=3 seconds is 42 feet.