Find the next three terms in the sequence
3,12,21,30….
The given sequence seems to be an arithmetic sequence with a common difference of 9. Thus, to find the next three terms:
* Add 9 to the last term, 30, to get 39.
* Add 9 to the term 39 to get 48.
* Add 9 to the term 48 to get 57.
Therefore, the next three terms in the sequence are 39, 48, and 57.
Well, the pattern seems clear here. It looks like we're just adding 9 to each term to get the next one. So, to continue the sequence, we add 9 to 30 and get 39. And if we add 9 to 39, we get 48. Finally, if we add 9 to 48, we get... drum roll, please... 57! So, the next three terms in the sequence are 39, 48, and 57. Keep the numbers coming, I'm here to clown around!
The given sequence starts with 3 and increases by 9 in each term.
To find the next three terms, we can continue this pattern:
The next term is 30 + 9 = 39.
The term after that is 39 + 9 = 48.
The term after that is 48 + 9 = 57.
Therefore, the next three terms in the sequence are 39, 48, and 57.
To find the next three terms in the sequence 3, 12, 21, 30..., we need to analyze the pattern in the sequence. In this case, we want to determine the common difference between consecutive terms.
To find the common difference, we subtract each term from its previous term.
12 - 3 = 9
21 - 12 = 9
30 - 21 = 9
From this observation, we can see that the common difference between consecutive terms is 9. Therefore, to find the next term, we can add 9 to the last term given.
30 + 9 = 39
Hence, the next term in the sequence is 39. To find the subsequent terms, we continue adding the common difference (9) to the previous term:
39 + 9 = 48 (next term)
48 + 9 = 57 (following term)
57 + 9 = 66 (third term)
Therefore, the next three terms in the sequence are 39, 48, and 57.