What would the graph of y = three-fourthsx – seven-eighths look like?
A. a straight line
B. a parabola
C. a curve
D. none of the above
A. a straight line. The equation is in slope-intercept form (y = mx+b), where the slope is three-fourths and the y-intercept is negative seven-eighths. This means the graph would start at negative seven-eighths on the y-axis and rise three units for every four units to the right, forming a straight line.
you ever think of just typing the math?
y = 3/4 x - 7/8
much cleaner than all those annoying words!
The graph of the equation y = three-fourthsx – seven-eighths will be a straight line. Therefore, the correct answer is A. a straight line.
To determine the graph of the equation y = (3/4)x - (7/8), we can consider the equation in slope-intercept form, which is y = mx + b. Here, m represents the slope, and b represents the y-intercept.
Given that in the equation y = (3/4)x - (7/8), the coefficient of x is 3/4, we can deduce that the slope of the graph is 3/4. This means that for every 1 unit increase in x, there will be a corresponding increase of 3/4 units in y.
To determine the y-intercept, we look at the constant term, which is -7/8. The y-intercept is the point on the graph where x is equal to 0. Hence, the y-intercept is (0, -7/8).
Using this information, we can begin plotting points on the graph. Starting from the y-intercept (0, -7/8), we move vertically downwards 7/8 units. From the y-intercept, the slope of 3/4 indicates that for every 1 unit increase in x, we move upwards 3/4 units.
By connecting the plotted points, we observe that the graph is a straight line. Therefore, the answer is A.