How many molecules are there in 352 grams of C2OH4?
the mol wt of C2OH4 is 44 g
so, how many moles in 352 g?
Now multiply that by 6.02*10^23
To determine the number of molecules in a given amount, we need to use the concept of Avogadro's number.
1. Start by calculating the molar mass of C2OH4:
- Carbon (C): 2 atoms x 12.01 g/mol = 24.02 g/mol
- Oxygen (O): 4 atoms x 16.00 g/mol = 64.00 g/mol
- Hydrogen (H): 4 atoms x 1.01 g/mol = 4.04 g/mol
Total molar mass = 24.02 g/mol + 64.00 g/mol + 4.04 g/mol = 92.06 g/mol
2. Calculate the number of moles:
Number of moles = given mass / molar mass
Number of moles = 352 g / 92.06 g/mol ≈ 3.82 mol
3. Apply Avogadro's number:
Avogadro's number represents the number of particles (molecules or atoms) in one mole of any substance:
Avogadro's number ≈ 6.022 x 10^23 particles/mol
4. Calculate the number of molecules:
Number of molecules = number of moles x Avogadro's number
Number of molecules = 3.82 mol x (6.022 x 10^23 particles/mol) ≈ 2.30 x 10^24 molecules
Therefore, there are approximately 2.30 x 10^24 molecules in 352 grams of C2OH4.
To determine the number of molecules in a given sample, you'll need to use Avogadro's number and the molar mass of the substance.
The molar mass of C2OH4 (ethylene glycol) can be calculated by summing the atomic masses of carbon, hydrogen, and oxygen:
(2 * atomic mass of carbon) + (4 * atomic mass of hydrogen) + (4 * atomic mass of oxygen).
By referring to the periodic table, we find:
Atomic mass of carbon (C) = 12.01 g/mol
Atomic mass of hydrogen (H) = 1.008 g/mol
Atomic mass of oxygen (O) = 16.00 g/mol
Now, we can calculate the molar mass of C2OH4:
(2 * 12.01 g/mol) + (4 * 1.008 g/mol) + (4 * 16.00 g/mol) = 62.07 g/mol.
Now that we know the molar mass of C2OH4, we can calculate the number of molecules using Avogadro's number, which states that there are 6.022 x 10^23 molecules in a mole:
Number of moles = mass / molar mass
Number of moles = 352 g / 62.07 g/mol = 5.66 mol
Number of molecules = number of moles * Avogadro's number
Number of molecules = 5.66 mol * (6.022 x 10^23 molecules/mol)
Number of molecules ≈ 3.41 × 10^24 molecules
So, there are approximately 3.41 × 10^24 molecules in 352 grams of C2OH4.