Question

The bearig of Q from P is 300° and the bearig of R from Q is 210°.if Q is equidistant from P and R, find the bearing of R from P

Answer 1

if you draw the diagram, you can see that ∆PQR is an isosceles right triangle, so ∡P = 45°

thus, the bearing of R from P is 300-45 = 255°