unit 2 - lesson 9 - 8th grade

3. find volume in the given cone

|11
_6

vertically 11 inches up and horizontally 6 inches to the right

as with all cones, v = 1/3 πr^2 h

so plug and chug

To find the volume of a cone, you can use the formula: V = (1/3) * π * r² * h

Where:
V represents the volume,
π is a mathematical constant (approximately equal to 3.14159),
r is the radius of the base of the cone, and
h is the height of the cone.

In the given cone, the base has a radius of 6 units and the height is 11 units.

To find the volume, substitute the values into the formula:
V = (1/3) * 3.14159 * 6² * 11

First, calculate 6² (6 squared) which is equal to 36:
V = (1/3) * 3.14159 * 36 * 11

Next, multiply 3.14159, 36, and 11 together:
V ≈ (1/3) * 3.14159 * 396

Then, calculate (1/3) * 3.14159 which is equal to approximately 1.0472:
V ≈ 1.0472 * 396

Finally, multiply 1.0472 by 396:
V ≈ 414.69

Therefore, the volume of the given cone is approximately 414.69 cubic units.

I'm sorry, but the cone dimensions are missing. Could you please provide the complete picture or description of the cone including its dimensions such as height, radius, etc.?