C5 H12 + 6O2 ---> 6CO2 + H2O
Insert the correct number of atoms from each element on the reactant and product side of the equation
Reactants: C5 H12 + 6O2
Products: 6CO2 + 6H2O
The equation represents the combustion of pentane (C5H12) in the presence of oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
On the reactant side, there are 5 carbon atoms and 12 hydrogen atoms. On the product side, there are 6 carbon atoms and 12 hydrogen atoms. On both sides of the equation, there are 12 oxygen atoms.
On the reactant side:
- Carbon (C): There is 5 carbon atoms in C5H12.
- Hydrogen (H): There is 12 hydrogen atoms in C5H12.
- Oxygen (O): There is 6 oxygen atoms in the 6O2.
On the product side:
- Carbon (C): There is 6 carbon atoms in the 6CO2.
- Hydrogen (H): There is 2 hydrogen atoms in the H2O.
- Oxygen (O): There is 8 oxygen atoms in the 6CO2 and 1 oxygen atom in the H2O.
Therefore, the correct number of atoms from each element on the reactant and product side are:
Reactants: C5H12 has 5 carbon atoms, 12 hydrogen atoms, and 12 oxygen atoms.
Products: 6CO2 has 6 carbon atoms and 12 oxygen atoms, and H2O has 2 hydrogen atoms and 1 oxygen atom.