If you spin the spinner below twice, what is P(vowel, then Q)?
A spinner is divided evenly into 6 sectors. From the top of the spinner clockwise, the sectors are labeled F, G, E, I, Q, and O. The spinner arrow points to the sector labeled Q.
A. one-tenth
B. one-ninth
C. start fraction 2 over 9 end fraction
D. start fraction 1 over 12 end fraction
9 / 18
The probability of landing on a vowel on the first spin is 2/6, because there are two vowels (E and I) out of the six sectors.
After the first spin, there are five sectors remaining, but only one leads to landing on a Q. Therefore, the probability of landing on Q on the second spin, given that a vowel was landed on the first spin, is 1/5.
To find the probability of both events happening, we multiply the probabilities:
P(vowel, then Q) = (2/6) x (1/5)
Simplifying this expression gives us:
P(vowel, then Q) = 1/15
Therefore, the answer is not listed, but the correct answer is:
Not listed. The probability is 1/15.
That's strange, I see 3 vowels,
E, I, and O
To determine the probability of spinning a vowel, then Q, we first need to find the probability of spinning a vowel and the probability of spinning Q.
Step 1: Find the probability of spinning a vowel:
Out of the 6 sectors on the spinner, only 2 are vowels (E and I). Therefore, the probability of spinning a vowel is 2/6 or 1/3.
Step 2: Find the probability of spinning Q:
Out of the 6 sectors on the spinner, only 1 is labeled Q. Therefore, the probability of spinning Q is 1/6.
Step 3: Find the probability of spinning a vowel, then Q:
To find the probability of spinning a vowel, then Q, we multiply the probability of spinning a vowel by the probability of spinning Q.
Probability of spinning a vowel, then Q = (1/3) * (1/6) = 1/18
Therefore, the answer is D. start fraction 1 over 12 end fraction.
To find the probability of spinning a vowel first and then spinning a Q, you need to determine the number of favorable outcomes and the total number of possible outcomes.
The favorable outcomes are when you spin a vowel (F, E, or I) followed by spinning a Q. There are 3 vowels and 1 Q, so the number of favorable outcomes is 3 (vowels) × 1 (Q) = 3.
The total number of possible outcomes is the total number of sectors on the spinner, which is 6.
Therefore, the probability of spinning a vowel, then Q is 3 (favorable outcomes) ÷ 6 (total outcomes) = 1/2.
So, the correct answer is A. one-tenth.