logx³-logx²=10 ??

To solve the equation log(x³) - log(x²) = 10, you can use the properties of logarithms.

Property 1: log(a) - log(b) = log(a/b)

Using this property, you can rewrite the equation as:

log(x³/x²) = 10

This simplifies to:

log(x) = 10

Now, to get rid of the logarithm, you can use the property:

If log_a(b) = c, then a^c = b.

In this case, the base of the logarithm is 10 (since there is no base written, it is assumed to be 10). So, you get:

10^10 = x

So, x = 10^10.