find the first four terms of the sequence using the equation 3n+5
To find the first four terms of the sequence using the equation 3n+5, we need to substitute the first four positive integer values of n into the equation and solve for each term.
1st term: n=1 → 3(1) + 5 = 8
2nd term: n=2 → 3(2) + 5 = 11
3rd term: n=3 → 3(3) + 5 = 14
4th term: n=4 → 3(4) + 5 = 17
Therefore, the first four terms of the sequence are 8, 11, 14, and 17.
To find the first four terms of a sequence using the equation 3n + 5, you need to substitute values of n into the equation.
Let's start with n = 1:
3(1) + 5 = 3 + 5 = 8
So, the first term of the sequence is 8.
Now, let's find the second term by substituting n = 2:
3(2) + 5 = 6 + 5 = 11
The second term of the sequence is 11.
For the third term, we substitute n = 3:
3(3) + 5 = 9 + 5 = 14
The third term of the sequence is 14.
Finally, for the fourth term, we substitute n = 4:
3(4) + 5 = 12 + 5 = 17
The fourth term of the sequence is 17.
Therefore, the first four terms of the sequence using the equation 3n + 5 are: 8, 11, 14, 17.
To find the first four terms of the sequence using the equation 3n+5, we substitute different values of n into the equation.
When n = 1,
Term 1 = 3(1) + 5 = 3 + 5 = 8
When n = 2,
Term 2 = 3(2) + 5 = 6 + 5 = 11
When n = 3,
Term 3 = 3(3) + 5 = 9 + 5 = 14
When n = 4,
Term 4 = 3(4) + 5 = 12 + 5 = 17
Therefore, the first four terms of the sequence using the equation 3n+5 are:
Term 1 = 8
Term 2 = 11
Term 3 = 14
Term 4 = 17