How to get sum of 8 terms of a linear sequence whose first term is 6 and last 48
The sum of 8 terms of a linear sequence whose first term is 6 and last 48 can be calculated using the formula for the sum of an arithmetic sequence.
Sum = (n/2)(a1 + a2)
Where n is the number of terms, a1 is the first term, and a2 is the last term.
In this case, n = 8, a1 = 6, and a2 = 48.
Sum = (8/2)(6 + 48)
Sum = (8/2)(54)
Sum = 432
impatient much?
Once is enough, thank you.
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