a 445 g sample of ice at -58 degrees celcious untill its temperature reaches -29 degrees celcius. find the change in heat content system
Note the correct spelling of celsius.
q = heat to move the temperature of 445 g ice from -58 to -29.
q = mass ice x specific heat ice x (Tfinal-Tinitial) = ??
To find the change in heat content of the system, we need to use the formula:
Change in heat content (Q) = mass (m) × specific heat capacity (c) × change in temperature (∆T)
In this case, the mass of the ice (m) is 445 g. The specific heat capacity of ice (c) is approximately 2.09 J/g°C. And the change in temperature (∆T) is the final temperature minus the initial temperature, which is (-29°C) - (-58°C).
Let's calculate the change in heat content step by step:
Step 1: Convert the mass from grams to kilograms:
Mass (m) = 445 g ÷ 1000 = 0.445 kg
Step 2: Calculate the change in temperature (∆T):
∆T = (-29°C) - (-58°C) = 29°C
Step 3: Plug the values into the formula:
Q = 0.445 kg × 2.09 J/g°C × 29°C
Step 4: Calculate the change in heat content (Q):
Q = 0.445 kg × 2.09 J/g°C × 29°C = 28.48605 J
Therefore, the change in heat content of the system is approximately 28.49 J.