The third, fourth and fifth oh geometric series is t+4,t+10,t+20 find the common difference
Common difference = 6
How did you come up with the answer
Hope you realize that the bot is wrong again
Your question should have asked for a "common ratio"
common difference refers to an arithmetic sequence
to have a GS, ...
t+4,t+10,t+20
(t+10)/(t+4) = (t+20)/(t+10)
t^2 + 24t + 80 = t^2 + 20t + 100
4t = 20
t = 5
the terms are : 9, 15, 25 , ..... and the common ratio is 5/3
To find the common difference of a geometric series, we need to examine the terms and find the pattern.
Given that the third term of the series is t+4, the fourth term is t+10, and the fifth term is t+20, we can subtract consecutive terms to find the common difference.
Let's subtract the third term from the fourth term:
(t+10) - (t+4) = t + 10 - t - 4 = 6
Now, let's subtract the fourth term from the fifth term:
(t+20) - (t+10) = t + 20 - t - 10 = 10
Since both subtractions result in constant values, we can conclude that the common difference of the geometric series is 6.